If it's not a typed dataset, then you probably want to do something like this, using the Linq-to-DataSet extension methods: var distinctValues = dsValues.AsEnumerable() . Select(row => new { attribute1_name = row. Field("attribute1_name"), attribute2_name = row.
Field("attribute2_name") }) .Distinct() Make sure you have a using System. Data statement at the beginning of your code in order to enable the Linq-to-Dataset extension methods Hope this helps!
If it's not a typed dataset, then you probably want to do something like this, using the Linq-to-DataSet extension methods: var distinctValues = dsValues.AsEnumerable() . Select(row => new { attribute1_name = row. Field("attribute1_name"), attribute2_name = row.
Field("attribute2_name") }) .Distinct(); Make sure you have a using System. Data; statement at the beginning of your code in order to enable the Linq-to-Dataset extension methods. Hope this helps!
I used attribute1_name there I am getting duplicate records – James123 Jul 14 '10 at 2:56.
Like this: (Assuming a typed dataset) someTable. Select(r => new { r. Attribute1_name, r.
Attribute2_name }).Distinct().
– Justin Niessner Jul 14 '10 at 2:09 @Justin: Not for a typed dataset. Tables in typed datasets inherit TypedTableBase, which implements IEnumerable. – SLaks?
Jul 14 '10 at 2:10 please provide me ... how iterate them – James123 Jul 14 '10 at 2:16 @James: foreach(var pair in ...) – SLaks? Jul 14 '10 at 13:43.
Check this link stackoverflow.com/questions/3234341/get-... Or try this var distinctRows = (from DataRow dRow in dTable. Rows select new col1=dRow"dataColumn1",col2=dRow"dataColumn2"}).Distinct().
You missed a {. – SLaks? Jul 14 '10 at 13:42.
Data; statement at the beginning of your code in order to enable the Linq-to-Dataset extension methods. Hope this helps!
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