An object at rest starts moves with constant acceleration 4m/s2. Find the distance travelled in the 4th second?

12/(2 + t)³ Then, when t = 4 we get: -12/(6)³ => -12/216 = -1/18 ft?² Remember that v(t) = d(s(t))/dt and a(t) = d(d(v))/dt :).

If x=3t/(2+t) then the velocity v=dx/dt and the acceleration is dv/dt. Using the quotient rule, dx/dt =3(2+t)-3t/(2+t)^2 =6/(2+t)^2=6(2+t)^-2 dv/dt = -12(2+t)^-3=-12/(2+t)^3 Sub t=4 to get the answer.

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