Calculate the mass of water produced when 8.57 of butane reacts with excess oxygen.?

2 C4H10 + O2 = 8 CO2 + 10 H2O moles C4H10 = 2.56 g / 58.124 g/mol=0.0440 the ratio between C4H10 and H2O is 2 : 10 moles water = 0.0440 x 10 / 2 = 0.220 mass water = 18.02 g/mol x 0.220 mol =3.97 g.

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