Calculate the volume of Hydrochloric Acid with stoichiometry?

Yep, you're right! Just include my explanation for your reference: MgCO? + 2HCl -----> MgCl?

+ CO? + H? O Moles of MgCO?

: 17.12/ 84 = .204 mol Volume of HCl: 2 * .204 / .406 = 1.004 L.

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