Circuito Eletrico misto? DESAFIO?

P = R*i² (temos que usar isso) ---- antes precisamos encontrar a corrente que sai, e pra isso temos que saber Req Calculando Req Paralelo: R4+R5 = R45 = 10 Série :R45 + R3 = R345 = 20 Paralelo :R345 + R2 = R2345 = 10 Série : R1 + R2345 = R12345 = 20 Req = 20 ohm U = Req*i I = 40/20 = 2A Quando essa corrente passa do R1, se divide x vai pra R2, y vai pra R345 ix + iy = 2 U2 = U345 --> R2*ix = R345*iy 20ix = 20iy ix = iy logo iy = 1A Quando esse 1 A passa por R3, chega num nó e se divide novamente z vai pra R4 e w para R5 enfim, como R4 = R5, a corrente se divide igualmente e chega 1/2 = 0,5 A na R5 ----- P = ri² P = 20 . (1/2)² = 5W.

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