Conditional operator issue?

Static_cast(c. GetD1()) : static_cast(c. GetD2())).

Yep, this works perfectly. – laura Nov 27 '09 at 9:08 1 You only need one of the casts here too, which makes the expression a little less verbose. – Richard Corden Nov 27 '09 at 19:20 @Richard, ah good note.To me it looks easier if I apply the cast to both operands, but you are of course right, one cast suffices to make the compiler see the other one can be converted to D& implicitly.

– Johannes Schaub - litb Nov 27 '09 at 20:42.

Btw, you don't really need to use a conditional operator, D* dptr; if(rand() %2 == 0) dptr = &c. GetD1(); else dptr = &c. GetD2(); D& d = *dptr; would work too.

This looks to be a little wasteful. Is there a benifit to this approach verses the Ternary operator? – Stephen Edmonds Nov 27 '09 at 9:52 This is true, but I find the code looks clunky if you do this (using the reference looks cleaner).

– laura Nov 27 '09 at 9:53 1 Stephen, I was only providing an answer in response to OP's "but I don't know how to get my reference to D without using the ternary operator" – Murali VP Nov 27 '09 at 9:54 2 I suspect this falls into the category "personal preference": I do find it less clunky, especially since in this case a normal (D&)-cast is enough (casting to base class) so the ternary operator is perfectly readable and you don't have an extra variable which will be unused later on. I'm not sure the cast qualifies as RTTI use. Your answer, however, is perfectly valid, I do not understand why it was down-voted.

– laura Nov 27 '09 at 10:27.

Or you can change the return types of the functions to Base Class.

This would pepper the rest of the code using the two getters with dynamic casts, it's not really a solution – laura Nov 27 '09 at 9:54 you are right, static_cast should work. – shyam Nov 27 '09 at 12:15.

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