¿Desde una distancia de 18.0m se observa un objeto situado a 4.5m de altura. ¿Cuál es el ángulo de elevación de?

(distancia del 2° observador al globo) c=150m (distancia entre los observadores) a=(c/sen C)sen A a=(150/0.9563)0.7313 a=(156.854)(0.7313) a=114.7 m b=(c/sen C)sen B b=(156.854)(0.866) b=135.8 m Para la altura, formamos 2 triangulos rectángulos de la base al globo. El triángulo de la izquierda: A=60° B=30° C=90° a=? (altura del gloobo) b=?

(distancia del 1er obsevador a la parte baja del globo) c=114.7m a=c sen A a=(114.7)(0.866) a=99.33 m.

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