Em um quadrado ABCD de lados iguais a 8 cm, calcule o raio do circulo que passa pelos vértices A e B ...?

Veja a figura os trapézios AOMD e BOMC ( são congruentes ) fazendo pitagoras no trapézio , tem BO² = OX² + BX² r² = 4² + ( 8 - r )² r² = 16 + 64 - 16r + r² 16r = 80 r = 5 ----------------------- > D.

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