Find the rms voltage across each element in an RLC circuit?

If the voltage source is DC, the inductor will indeed short it out. You can only work out this type of problem with an AC voltage source. At t =0 when the switch is opened disconnecting the voltage source, I inductor (0+) = I inductor (0+) since current can't change instantly in an inductor, and Vc (0+) = Vc(0-) since the voltage across a capacitor can't change instantly For a parallel circuit Vc = Vr = Vl = V I ind = (1/L)(?V dt), Ir = V/R, Ic = C dV/dt I = I ind + Ir + Ic This can be solved with Laplace Transforms I(s) = V(s)(1/(sL) + 1/R + sC) - Vc(0+) + I inductor (0+)/s.

The battery is short circuited through the inductor, will not work.

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