Four fair dice are rolled at the same time. What is the probability that at least one of the dice will show 3? Asked by Tierra2011 2 months ago Similar questions: fair dice rolled time probability show Games & Leisure > Board Games.

Similar questions: fair dice rolled time probability show.

The probability that at least one will show a 3 is the inverse probability (1 minus whatever you got).

1 chance out of 6 x 4 dice = 4 chances out of 6.

Probability theory really got going in 1654 with a famous correspondence between the two famous mathematicians Blaise Pascal and Pierre de Fermat, sparked off by a gambling addict by the name of Antoine Gombaud, who went by the name of the “Chevalier de Méré” (although he wasn’t actually a nobleman of any sort). The Chevalier de Méré had played a lot of dice games in his time and, although he didn’t have a rigorous mathematical theory of how they worked, he nevertheless felt he had an intuitive “feel” for what was a good bet and what wasn’t. In particular, he had done very well financially by betting at even money that he would roll at least one six in four rolls of a standard die.It’s quite an easy matter to use the rules of probability to see why he was successful with this game.

The odds that a single roll of a fair die yields a six is 1/6. The probability that it does not yield a six is therefore 5/6. The probability that four independent rolls produce no sixes at all is (the probability that the first roll is not a six) times (the probability that the second roll is not a six) times (the probability that the third roll is not a six) times (the probability that the fourth roll is not a six).

Each of the probabilities involved in this multiplication is 5/6, so the result is (5/6)^4 which is 625/1296. But this is the probability of losing. The probability of winning is 1-625/1296 = 671/1296=0.5177, significantly higher than 50%.

Since you’re more likely to win than lose, it’s a good bet. "http://telescoper.wordpress.com/tag/chevalier-de-mere/ com/tag/chevalier-de-mere.

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Three dice are rolled. Find the number of possible outcomes in which at least 1 dice shows 4.

If a die is rolled four times, what is the probability it lands on 6 on the 1st,3rd and 4rth roll but not on the 2nd rol.

It's state fair time again, and that means.....FAIR FOOD!

Determine the probability that on rolling 3 dice that the highest die will be 6 and the next highest 4.

If roll a dice four times. What is the probability of rolling 1, 2, 3, and 4?

It's getting closer to Fair time here! (see details).

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