You'll need to change while ((xSquare + squareSize) >= xRing && xSquare = yRing && ySquare.
Thanks, but it keeps overlapping! – RCola Dec 3 at 17:16 why do you assume that "ringSize is the radius of the circle, not the diameter. " - it is the value of weight and height, and they equal each other - therefore it is diameter!
– RCola Dec 3 at 17:31 @RCola OK, I checked the API: ringSize is the diameter. Check my new condition; I think it will work. I guess you always had overlaps with a square to the left (or higher) of the ring, which I fixed.
– toto2 Dec 3 at 17:38 I don't understand how, but this solution works. Any ideas? – RCola Dec 3 at 17:39 You can have a square with its left edge to the left of the ring, but the right edge of the square is inside the ring.
Your original condition considered that a non-overlap, mine does. – toto2 Dec 3 at 17:43.
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