How to use regular expression extract the number inside the ()?

Regular expressions provide ways to capture buffers. Check this document on how to capture buffers with Perl, which is pretty universal Basically, you need to wrap up the piece of regex you want to capture in unescaped parenthesis: (\(\d*\)) By convention, in buffer 0 you'll have the whole string, and in buffer 1 you'll have the first captured buffer.

Regular expressions provide ways to capture buffers. Check this document on how to capture buffers with Perl, which is pretty universal. Basically, you need to wrap up the piece of regex you want to capture in unescaped parenthesis: (\(\d*\)) By convention, in buffer 0 you'll have the whole string, and in buffer 1 you'll have the first captured buffer.

This should do it. \((.*)\) The first group will be the value inside the brakets -- an example of usage in javascript var test = 'sfsfsdfsdf(12a)sdfsdfsdf'; var r = test. Match(/\((.*)\)/) console.

Log(r1).

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