How would an angle decrease in Valence Bond Theory when going from CH4-H2O. In VSPER its due to lone pair repulsion.?

If you add an insoluble base to water (for example, Ca(OH)2), it dissolves very slightly, establishing an equilibrium as: Ca(OH)2(s) Ca2+(aq) + 2 OH-(aq) Because the equilibrium constant for this reaction (the Ksp) is small, very little of the base dissolves. Now, if you add the base to a solution of acid, the OH- that are produced as the base dissolves react with H+ of the acid to form water. This shifts the solubility equilibrium to the right (think about LeChatlier's Principle), causing more of the base to dissolve.

Written another way, the reaction of any base with an acid produces water and a salt. So, if we add Ca(OH)2 to HCl, this reaction takes place: Ca(OH)2(s) + 2 HCl(aq) --> CaCl2(aq) + H2O(l) Hope that helps...

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