Inputing advanced sql quries in table - not unique table alias mysql?

It looks like your string concatenation misses spaces so the first two lines would give ... cinema, relationship, moviewhere cinema. City = city.id. In that case sql reads twice cinema ... Could it be as simple as this?

I would echo the query before sending it.

Yes, you were right on that! However, new error came accross. Warning: mysql_fetch_array() expects parameter 1 to be resource, string given in file.

Php on line 75. Line 75: while($result = mysql_fetch_array( $query )) { Checked sql result, it gives 0, no entries. – bojar Dec 4 at 17:06 mysql_query takes 2 parameters, the second being the connection handle, that's what's missing.In your included mysql_con.

Php there must be a line like $cx = mysql_connect($host, $user, $password), you need to call mysql_query ($query, $cx). – gregory Dec 4 at 18:04.

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