Pls I don't know how to find the exterior angle of a polygon?

F(x) = (cscx - secx)/(1 - tanx). Pus s - sinx, c = cosx, then f(x) = (1/s - 1/c)/(1 - s/c) and (sc^2)f(x) = (c - s)^2 = c^2 + s^s - 2sc = 1 - 2sc = 1 - 2s(1 - s^2)^(1/2) and f(x) = 1 - 2s(1 - s^2)^(1/2)/s(1 - s^2).

I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.

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