UITableView load cells reverse?

Maybe you should perform it at your table's data source method: (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { ... NSUInteger row = indexPath row; NSUInteger count = listData count; // here listData is your data source cell.textLabel. Text = listData objectAtIndex:(count-row-1); return cell; }.

Maybe you should perform it at your table's data source method: - (UITableViewCell *)tableView:(UITableView *)tableView cellForRowAtIndexPath:(NSIndexPath *)indexPath { ... NSUInteger row = indexPath row; NSUInteger count = listData count; // here listData is your data source cell.textLabel. Text = listData objectAtIndex:(count-row-1); return cell; }.

I think it should be (count-1-row). – DyingCactus May 11 '10 at 2:39 you're right. :) my mistake.

I'll update that. – Elliot Chen May 11 '10 at 2:41 This will be accessing the opposite number in the data? – Jaba May 11 '10 at 3:03 I think so.

If you use NSArray or its subclass to hold your data source. And also you can use 'reverseObjectEnumerator'. If you use other kind of data structures to hold your data, you need to use a corresponding 'reverse' accessing method.

– Elliot Chen May 11 '10 at 3:41 (count-1-row) and (count-row-1) isn't that the same? It's like (10 - 1 - 4) and (10 - 4 - 1) that would both give the difference of 5. – Jay Q.

May 11 '107 at 6:55.

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