Here's one way: >> p = 9; >> startrow = find(A(:, 3) == p, 1); % first row where 3rd column entry is p >> A1 = A(startrow:end, :) A1 = 7 8 9 2 3 4 3 4 5 1 6 8 Edit: With multiple entries of p in the last column, you can vary how find is used. For example, if you want to start at the last p instead of the first, you could run >> startrow = find(A(:, 3) == p, 1, 'last'); % last row where 3rd column entry is p If you want the second from first, you'd need a little more work: >> startrows = find(A(:, 3) == p, 2); % first two rows where 3rd column entry is p >> startrow = startrows(end); % Just the second row where 3rd column entry is p Also, you probably need error checking if there is the possibility that p never appears in the array, or doesn't appear at least two times (for the last example).
– chee Oct 25 '10 at 17:21 A1 = A(1:startrow, :); – SCFrench Oct 25 '10 at 18:30.
If you know what column the point is from you can simply do B = A(n:end,:) where n is the column number.
Another option is to delete the rows directly from the original matrix: A(1:startrow-1,:)=.
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