If you try to plot these points on the Calculator and fit the best line of fit you will see that relation between the two variable is more quadratic, not exponential for me I get Breaking distance D = 0.0065s² + 0.1809s - 4.9071 if you calculate the stopping distance using this formula for speed = 20km/sec stopping distance is = 1.31m (actual is 0.8 m) for speed = 30km/sec stopping distance is = 6.37 m (actual is 7.2 m) for speed = 40km/sec stopping distance is = 12.73 m (actual is 12.8 m) for speed = 50km/sec stopping distance is = 20.39 m (actual is 20.0 m) for speed = 60km/sec stopping distance is = 29.35 m (actual is 28.8 m) for speed = 70km/sec stopping distance is = 39.61 m (actual is 39.9 m) the R² value for the fit is 0.9986 which is very good and the value of stopping distance for s = 90 fore-casted will be D = 64.02 m Converting the speed from Km/hr to M/sec will not really effect much to the equation and values I tried and still my answer of stopping distance at 90km /hr or 25 m/sec I get 63.9 meter which is very close to what we get here ie. 64 meter - hence truck will not be able to avoid the stone seen at 50m while travelling at 90 km /he (even neglecting the response time) Hope this helped Vick.
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.