Topological sorting is a post-order traversal of trees (or directed acyclic graphs).
Topological sorting is a post-order traversal of trees (or directed acyclic graphs). The idea is that the nodes of the graph represent tasks and an edge from A to B indicates that A has to be performed before B. A topological sort will arrange these tasks in a sequence such that all the dependencies of a task appear earlier than the task itself.
Any build system like UNIX make has to implement this algorithm. The example that Dario mentioned — destroying all nodes of a tree with manual memory management — is an instance of this problem. After all, the task of destroying a node depends on the destruction of its children.
This is a great answer. Remembering that trees are degenerate graphs opens up all kinds of functionality. And topological sorting is hugely useful.
– Plutor Aug 23 '10 at 13:57 Why is it called topological sorting instead of, say, scheduling or something, or what is "Topological" supposed to mean in this context? – Shawn Apr 30 at 3:08 @Shawn: Beats me. It's probably because only the topology of the graph/network matters.
– Heinrich Apfelmus May 3 at 18:12.
Post order is (can be) used by compilers. Consider an expression tree for a + be + c, the machine language would require a sequence like a be + c +. This is also called Reverse polish Notation (RPN).
On the Wikipedia page it says: "RPN aka Postfix" Post-order is required for destroying a tree, just like pre-order is needed to create/clone it.
1 Destroying a tree, that's a good point. – Plutor Aug 20 '10 at 16:08 +1 Its like you can clone a tree using pre order and destroy it using the reverse steps i.e. Post order.
There should be some other areas where pre/post order would be very efficient. – Lazer Aug 20 '10 at 22:38.
As Henk Holterman pointed out, destroying a tree using manual memory management usually is a post-order traversal. Pseudocode: destroy(node) { if (node == null) return; destroy(node. Left) destroy(node.
Right) // Post-order freeing of current node free(node) }.
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