1. To get ln(2), plug in x = 1, and we can get an approximation: ln(1 + 1) = ln(2)? (1) - (1/2)(1)^2 + (1/3)(1)^3 5/6 For ln(17/5), recall that -ln(a) = -ln(1/a), so we can calculate ln(5/17) and take the negative of that for ln(17/5): ln(1 - 12/17) = ln(5/17)?
(-12/17) - (1/2)(-12/17)^2 + (1/3)(-12/17)^3 -5268/4913 ln(17/5)? 5268/4913 So we get: x = ln(17/5)/ln(2) + 3.
Hey it is very hard to work out on this problem and get the value of x.....we have to go through number of hit and trial until and unless the value in the left hand side equates to the right...Daniel is right, that's what I can do and get the value by using calculator.... If your question was like this 5* 2^(x-3) = 20 then I get the value for x without using a calculator. Like, 2^(x-3) = 20/5 2^(x-3) = 4 2^(x-3) = 2^2 when bases are equal (here it's 2) we can equate respective indices So, x-3 = 2 x = 5 Sorry cannot help you out....if anyone solves this question manually other than hit and trial method I really wanna learn that technique....:)).
I cant really gove you an answer,but what I can give you is a way to a solution, that is you have to find the anglde that you relate to or peaks your interest. A good paper is one that people get drawn into because it reaches them ln some way.As for me WW11 to me, I think of the holocaust and the effect it had on the survivors, their families and those who stood by and did nothing until it was too late.