You have a bucket of water weighing 10 pounds. You put a live 10 pound fish in it. How much does the bucket now weigh?

The bucket, presumably made of plastic or metal, is not altered by addition or removal of contents. So the first persnickity answer is, "same as before the fish was added". The fish will displace 10 lbs of water, if it floats even slightly above the surface of the water.

If it sinks, or floats below the surface, you can be sure it displaced less than 10 lbs of water (else it would be floating above the surface. ) So answer number two is, 20 lbs - ASSUMING the bucket is large enough to prevent any over flow. Third answer, for small bucket owners, is same as number two, less the weight of any water that spilled out when you put the fish in.

You have a bucket of water weighing 10 pounds. You put a live 10 pound fish in it. How much does the bucket now weigh?

I have never been able to get a satisfactory answer to this. Some say 20 pounds, but since the fish does not touch the bucket how can this be? Some say it weighs the amount of the water displaced by the fish.

So where does the rest of the weight go? I would like to know the difinitive answer. Thanks.

Jack Asked by Montalguy 30 months ago Similar Questions: bucket water weighing 10 pounds put live pound fish weigh Recent Questions About: bucket water weighing 10 pounds put live pound fish weigh Science.

Similar Questions: bucket water weighing 10 pounds put live pound fish weigh Recent Questions About: bucket water weighing 10 pounds put live pound fish weigh.

If the bucket previously was exactly full, then it now weighs ten pounds *plus* the difference between the ..... weight of the fish and the weight of the water that the fish displaced. Even though the fish might not physically touch the sides or bottom of the bucket, the force generated by the mass of the fish is exerted on the water and transmitted to the sides and bottom of the bucket by the water. If the bucket was not previously full, and, after the fish is placed in it, it still is not full, then the bucket now weighs twenty pounds, because no water was displaced out of the bucket.

These answers would be unaffected by the fish's being dead instead of alive.

If the ten pounds of water is to the brim, adding the fish will have to subtract the weight of water displaced and sloshed over the side. Thus, your question is unanswerable without more details.

Ok, the easy answer, provided that the bucket is large enough to hold both the fish and the water, is the final total is 20 pounds. The water level will be higher, but the weight will be the weight of the water and the fish. If yu want to try this yourself, get a bucket.

Weight the bucket. Fill it half with water. Weight the bucket and the water.

Get another smaller container and weight it. Fill the small container with sand, marbles, rocks, whatever and weight it. Now, add whatever is in the smaller container into the bigger container, and weight it.

The big container will not weight what the container weighed, plus what the water weighed plus whatever was in the smaller container weighed. BTW, a 20 pound fish would never fit in a container that contains only 10 pounds of water - That's about a gallon and a quarter of water. A 20 pound fish is about 3 feet long.

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Easy There's a principle called conservation of mass. On Earth, it can also be loosely called conservation of weight. Weight does not just disappear.

Now do a thought experiment. Let's say the fish weighs ten pounds but is light enough to float. Hold the fish by the tail and slowly lower it into the bucket.

At first your arm is supporting ten pounds. When you're done lowering the fish, it floats, so your arm is then holding up NO pounds. So as you were lowering it, the effective weight of the fish must have gone down from ten to zero pounds.

SOMETHING was taking up the weight of the fish. You might go Eureka, like Archimedes, and realize the water mush be pushing up to support the weight that your arm is no longer supporting. So when the fish is fully in the water and floating freely, not on the surface, not on the bottom, it must weigh exactly as much as its volume of water.

If it weighted a bit less, it would float to the top. If it weighed just a bit more, it would sink to the bottom. Since it's floating in the middle, it must weight EXACTLY as much as its volume of water.

Which means--- you could replace the fish with exactly its volume of water and nothing would change. Soooooo you've added ten pounds of water to the bucket, which now has 20 pounds of water in it. Voila' and touche'.

10 lbs The fish will displace the weight od the lost water; this is assumong that the bucket was full. Sources: rednecksputter, Phill-oss-a-fur, read some, been places .

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