What is the value of g at a distance from the Earth's center equal to 4 times the Earth's radius if the value of g at the earth's surface is about 9.8 meters per second squared?

The gravitation field varies inversely with the square of distance, in this case as measured from the Earth's center. We live on the surface, which is at a distance of 1R where R is the radius. At a distance 4 times greater (4R), the force would fall to 1/4^2 = 1/16 time g.

(9.8)/16 = etc.

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