What is the value of g at a distance of twice the earth's radius if the value of g on the earth's survace is about 9.8 meters per second squared?

We know that, g1=G. M/R2so, g is inversely proportional to R2. And, if Radius of the earth(R) is doubled, the distance between the object and the centre of the earth will become 2R.

Now, g=G. M/(2R)2 => g2=G. M/4R 2 => g2=1/4(G.

M/R2) Since, G. M/R2 =g1 => g2=1/4 g1 Here, g1=9.8 m/s2 So, g2=9.8/4 m/s2 =2.45 m/s2.

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