Java: extract Alpha Channel from BufferedImage?

I don't believe there's a single method call to do this; you would have to get all the image data and mask off the alpha byte for each pixel. So for example, use getRGB() to get the ARGB pixels for the image. The most significant byte is the alpha value.So for each pixel in the array you get from getRGB() int alpha = (pixel >> 24) & 0xFF.

I don't believe there's a single method call to do this; you would have to get all the image data and mask off the alpha byte for each pixel. So for example, use getRGB() to get the ARGB pixels for the image. The most significant byte is the alpha value.So for each pixel in the array you get from getRGB(), int alpha = (pixel >> 24) & 0xFF.

Ok, thanks. How would I mask off the alpha byte from one pixel? – clamp May 30 at 12:59 Added a little more detail.

– Ernest Friedman-ll May 30 at 13:06 I think this is possible without manually looping over the pixels which might result in better performance on some platforms, see my answer. – Waldheinz May 30 at 13:11.

Not tested but contains the main points. Public Image alpha2gray(BufferedImage src) { if (src.getType()! = BufferedImage.

TYPE_INT_ARGB) throw new RuntimeException("Wrong image type. "); int w = src.getWidth(); int h = src.getHeight(); int srcBuffer = src.getData(). GetPixels(0, 0, w, h, null); int dstbuffer = new intw * h; for (int i=0; i> 24) & 0xff; dstBufferi = a | a >> 8 | a >> 16; } return Toolkit.

GetDefaultToolkit(). CreateImage(new MemoryImageSource(w, h, pix, 0, w)); }.

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