Please help me! I'm in major need of help for my algebra homework?

Please help me! I'm in major need of help for my algebra homework. I am really confused about how to do it and I have a test tommorrow.

Here's the question: (c+3c^2)(-c^2) please help me and explain how it's done. Asked by chief 50 months ago Similar questions: help major algebra homework Science > Math.

Similar questions: help major algebra homework.

Distributive property of multiplication The distributive property of multiplication states that: X * (Y + Z) = (X * Y) + (X * Z) So in this case, you want to distribute -C² over the polynomial (C + 3C²): -C² * (C + 3C²) = (-C² * C) + (-C² * 3C²) Let's do the first binomial first: (-C² * C). First, a negative times a positive is always negative. Second, when you multiply two numbers, you add the exponents.So this binomial reduces to -C³.

The second binomial is (-C² * 3C²). Again, negative times positive is negative.So the constant part will be -3. And the sum of the two exponents is 4.

So this reduces to -3C^4.(Sorry, I don't have a superscript-four on this keyboard). So our two binomials reduced to -C³ and -3C^4. The sum of these two can not be reduced any further, so our final answer is: -C³ + -3C^4.

Hope that helps! Sources: Math .

Here it is, step by step You must distribute the multiplication. The negatives and exponents are a complication. When you multiply 2 items with the same variable, you add the exponents of the variable.

If there is no exponent over the variable, then the exponent is 1. (c + 3c^2) * (-c^2) Multiply each of the 2 items in the first set of parentheses with the item in the second set of parentheses: (c * (-c^2)) + (3c^2 * (-c^2)) First multiplication: c * (-c^2) = 1c^1 * (-1c^2) ______Here I have shown the factors and exponents of 1 that are normally not written. 1 * (-1) = -1 and c^1 * c^2 = c^(1 + 2) = c^3___Here I have separately multiplied the factors together and the variables together.(c * (-c^2)) = -1c^3 or -c^3 Second multiplication: 3c^2 * (-c^2) = 3c^2 * (-1c^2)______Here I have shown the factor of 1 that is normally not written.3 * (-1) = -3 and c^2 * c^2 = c*(2+2) = c^4___Here I have separately multiplied the factors together and the variables together.(3c^2 * (-c^2)) = -3c^4 The answer: (c + 3c^2) * (-c^2) = -c^3 - 3c^4 I hope this helps..

’Please Excuse My Dear Aunt Sally’ is the mnemonic they taught us, for Parentheses - Exponents - Multiplication/Division - Addition/Subtraction, which is the order you need to follow. (1) Parentheses group together parts of the two factors to be multiplied here; they are used whenever you might otherwise get confused, to remind you what to do first; (2) Do NOT separate the exponents from the rest of the term! Remember also that multiplying exponents, is the same as adding those exponents (example: 2^3 x 2^4 = 2^7, because 2^3 = 2 x 2 x 2 and 2^4 = 2 x 2 x 2 x 2.

That’s seven 2’s multiplied together, or 2^7) (3) Do all multiplication & division BEFORE you do any addition or subtraction (example: 5 x 5 + 2 = 27. If you do the addition first, it’s 5 x 7 = 35.By convention, M/D comes before A/S) (c + 3c^2) x (-c^2) OK, to the specifics of this question. I find it easier to break it down to smaller parts: expand the expression to make it easier to understand.

By breaking the first "bloc" into two parts, you can move that + sign... ((c) x (-c^2)) + ((3c^2) x (-c^2)) Next, we can pull off the integers: I wouldn’t bother with "1 x" anything, except that we have a negative sign here... ((c) x (-1 x c^2)) + ((3 x c^2) x (-1 x c^2)) By the same token, "^1" usually goes unwritten, but can be helpful to see... ((c^1) x (-1 x c^2)) + ((3 x c^2) x (-1 x c^2)) So, we can regroup the integers... (-1 x (c^1) x (c^2)) + ((3 x -1) x (c^2 x c^2)) ...and get rid of some of these parentheses... (-1 x c^1 x c^2) + (-3 x c^2 x c^2) Now, group the exponents... (-1 x c^(1 + 2)) + (-3 x c^(2 + 2)) Add them together: remember, it’s the same as multiplying these c’s themselves (-1 x c^3) + (-3 x c^4) Get rid of the multiplication signs... (-c^3) + (-3c^4) And finally, get rid of the remaining parentheses, paying attention to the negative signs... -c^3 - 3c^4 I realize this explanation may leave you with one or two questions, and is probably too late to help you on your test.My parents would have had something to say to me about that... Sources: Treasured memories of high school algebra .

Double Distribution While most people call this FOIL, I like to think of it as double distribution. Each of the terms in the first binomial (the first set of parentheses) must be distributed over the second set of parentheses: c * (-c^2) + 3c^2*(-c^2) or c*(-c)*c + 3*c*c*(-c)*c -c^3 + -3c^4 Remember, in math there’s almost always more than one way to do a problem! Sources: B.S.Mathematics, minor in Math Ed..

You just multiply the -c^2 through the whole first phrase. So you'd get -c^3-3c^4. I think that's what they're asking.

Sources: me .

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Please help me! I'm in major need of help for my algebra homework. I am really confused about how to do it and I have a test tommorrow.

Here's the question: (c+3c^2)(-c^2) please help me and explain how it's done. Asked by chief 51 months ago Similar questions: help major algebra homework Science > Math.

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