Please help me with this mathematics question. Thanks.?

(a) Find the equation of the tangent at the point (1,2) on the curve y = x³ + 3x - 2 (b) Use your GCD to find the coordinates of the point where this tangent meets the curve again. SOLUTION From the given equation. Y = x³ + 3x - 2 Differentiate to find the slope.

Dy/dx = 3x² + 3 When x = 1 (From the given point) dy/dx = 3(1)² + 3 dy/dx = 3(1) + 3 dy/dx = 3 + 3 dy/dx = 6.

Y = x³ + 3x - 2 tangent at the point (1, 2) y' = 3x² + 3 at x = 1, the slope of the tangent line = 6 (y - 2) = 6(x - 1) or y = 6x - 4 the line intersects the curve at: 6x - 4 = x³ + 3x - 2 x³ - 3x + 2 = 0 (x - 1)² (x + 2) = 0 x = - 2...so, y = - 16 (- 2, - 16) is the other point of intersection. If you have more maths question use mathqu homework support app in app store this is the best app to get answers from live tutors who write step by step maths answers search for mathqu in app store.

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