Quick Mathematics Question! Please Help! Thanks!?

NOTE: e, cannot tends to infinity. ... it is x that can tends to infinity. E^3x+6e^2x-4e^x/(e^x-e^4x) x?

+? (e^x)³ + 6(e^x)² - 4e^x/e^x - (e^x)? X?

+? Let , e^x = you Therefore (u³ + 6u² - 4u)/(u - u?) you? +?

U(u² + 6u - 4)/u(1 - u³) you? +? (u² + 6u - 4)/(1 - u³) you?

+? Divide both numerator and denominator by the highest power of u.

I think you meant : x goes to infinity ( not e goes to infinity ) if so, the answer is : say u= e^x then the upper line's higher power is : u^3 and the lower's higher power is -u^4 since the lower line has a higher power than the upper, this means the final answer is Zero.

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