Trig homework. Need some help?

Ok, go back to the 3rd step where you had (cos x + cos^2 x + sin^2 x)/sin x (cos x + 1) = csc x Remember, sin^2 x + cos^2 x = 1, so substitute in the numerator to get: (cos x + 1)/sin x(cos x + 1) = csc x Now cancel the (cosx +1)'s to get 1/sin x = csc x csc x = csc x.

Okay, im starting at (cosx+cos^2x+sin^2x)/(sinx+cosxsinx) well cos^2x+sin^2x=1 so (cosx+1)/sinx(1+cosx)..........(1+cosx... cancel each other 1/sinx=cscx I think thats right hope I could help.

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